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Not so obvious to everyone. There are a number of people here who are equally educated in mathematics who come up with different answers.
Yes, exactly! I'm still stuck on interpreting the original expression as the first example you have. Others are seeing it as in the second example...
I think that's my problem. I do not see 6÷2x3=x to be the same as (6÷2)x3=x The first one has 2x3 in the denominator (6/6) where the second has...
That's exactly how I'm seeing it and why I keep getting x = 1 no matter what method or calculator I use. I tried a few times to get x = 9 (which I...
0.125 is what I get, too. Not sure how to see it any other way.
The HP-41C is amazing. I think I was in my first year of college. I had been using a Ti-55. I took a summer course called something like "advanced...
Interesting article. The article states, "If you calculate the problem using this convention, it’s 6 divided by (2(1+2)), which is 1. Typically,...
So you have me thinking ... ok, how does having the denominator as (ab) + (ac) differ from having 'a' factored out? Doesn't (ab)+(ac) = a(b+c)?...
In Fields and Waves, I got dinged on an answer because I put 1/(2*pi) which was the correct answer. My teacher said that I was supposed to write...
In physics, if we weren't sure of an answer, we would say ... just divide by pi and that's your answer :-)
' Awesome, I love that stuff (although it's been a while)!
It's because e^(i*pi) + 1 = 0. That is what makes Strats quack in positions 2 and 4 o_O
> It always amazes me how people want to try to redefine absolute truth. These redefinitions cause nothing but division even among the people that...
I think the picture under the amp is the fundamental theorem of calculus (at least differential calc).
The square root of -1 = i
The video is correct ... Parenthesis, multiplication, division, addition, subtraction 6/2(1 + 2) = 6/2(3) = 6/6 = 1
Because it's ... 6/2(1 + 2) = 6/2(3) = 6/6 = 1
1. Repo Man 2. Eraserhead
I Want A Love I Can See - Temptations (1963) https://www.youtube.com./watch?v=l_ZS44hix_g